Add solution to problem six

six.adb

@@ -0,0 +1,53 @@
+--
+--  Project Euler problem #6
+--
+--  The sum of the squares of the first ten natural numbers is,
+--
+--      1^2 + 2^2 + ... + 10^2 = 385
+--
+--  The square of the sum of the first ten natural numbers is,
+--
+--      (1 + 2 + ... + 10)^2 = 55^2 = 3025
+--
+--  Hence the difference between the sum of the squares of the first ten
+--  natural numbers and the square of the sum is 3025  385 = 2640.
+--
+--  Find the difference between the sum of the squares of the first one hundred
+--  natural numbers and the square of the sum.
+
+
+with Ada.Text_IO;
+
+use Ada.Text_IO;
+
+procedure Six is
+    Ceiling : constant Natural := 100;
+
+    function Sum_Of_Squares (Upper_Bound : in Natural) return Natural is
+        Result : Natural := 0;
+    begin
+        for Step in 1 .. Upper_Bound loop
+            Result := (Result + (Step ** 2));
+        end loop;
+        return Result;
+    end Sum_Of_Squares;
+
+    function Square_Of_Sums (Upper_Bound : in Natural) return Natural is
+        Result : Natural := 0;
+    begin
+        for Step in 1 .. Upper_Bound loop
+            Result := (Result + Step);
+        end loop;
+        return Result ** 2;
+    end Square_Of_Sums;
+begin
+    declare
+        Left : constant Natural := Sum_Of_Squares (Ceiling);
+        Right : constant Natural := Square_Of_Sums (Ceiling);
+    begin
+        Put_Line ("Sum of squares:" & Natural'Image (Left));
+        Put_Line ("Square of sums:" & Natural'Image (Right));
+        New_Line;
+        Put_Line ("Difference:" & Natural'Image (Right - Left));
+    end;
+end Six;