book/nostarch/chapter10.md

76 KiB
Raw Blame History

[TOC]

Generic Types, Traits, and Lifetimes

Every programming language has tools for effectively handling the duplication of concepts. In Rust, one such tool is generics: abstract stand-ins for concrete types or other properties. We can express the behavior of generics or how they relate to other generics without knowing what will be in their place when compiling and running the code.

Functions can take parameters of some generic type, instead of a concrete type like i32 or String, in the same way they take parameters with unknown values to run the same code on multiple concrete values. In fact, weve already used generics in Chapter 6 with Option<T>, in Chapter 8 with Vec<T> and HashMap<K, V>, and in Chapter 9 with Result<T, E>. In this chapter, youll explore how to define your own types, functions, and methods with generics!

First well review how to extract a function to reduce code duplication. Well then use the same technique to make a generic function from two functions that differ only in the types of their parameters. Well also explain how to use generic types in struct and enum definitions.

Then youll learn how to use traits to define behavior in a generic way. You can combine traits with generic types to constrain a generic type to accept only those types that have a particular behavior, as opposed to just any type.

Finally, well discuss lifetimes: a variety of generics that give the compiler information about how references relate to each other. Lifetimes allow us to give the compiler enough information about borrowed values so that it can ensure references will be valid in more situations than it could without our help.

Removing Duplication by Extracting a Function

Generics allow us to replace specific types with a placeholder that represents multiple types to remove code duplication. Before diving into generics syntax, lets first look at how to remove duplication in a way that doesnt involve generic types by extracting a function that replaces specific values with a placeholder that represents multiple values. Then well apply the same technique to extract a generic function! By looking at how to recognize duplicated code you can extract into a function, youll start to recognize duplicated code that can use generics.

Well begin with the short program in Listing 10-1 that finds the largest number in a list.

Filename: src/main.rs

fn main() {
  1 let number_list = vec![34, 50, 25, 100, 65];

  2 let mut largest = &number_list[0];

  3 for number in &number_list {
      4 if number > largest {
          5 largest = number;
        }
    }

    println!("The largest number is {largest}");
}

Finding the largest number in a list of numbers

We store a list of integers in the variable number_list [1] and place a reference to the first number in the list in a variable named largest [2]. We then iterate through all the numbers in the list [3], and if the current number is greater than the number stored in largest [4], we replace the reference in that variable [5]. However, if the current number is less than or equal to the largest number seen so far, the variable doesnt change, and the code moves on to the next number in the list. After considering all the numbers in the list, largest should refer to the largest number, which in this case is 100.

Weve now been tasked with finding the largest number in two different lists of numbers. To do so, we can choose to duplicate the code in Listing 10-1 and use the same logic at two different places in the program, as shown in Listing 10-2.

Filename: src/main.rs

fn main() {
    let number_list = vec![34, 50, 25, 100, 65];

    let mut largest = &number_list[0];

    for number in &number_list {
        if number > largest {
            largest = number;
        }
    }

    println!("The largest number is {largest}");

    let number_list = vec![102, 34, 6000, 89, 54, 2, 43, 8];

    let mut largest = &number_list[0];

    for number in &number_list {
        if number > largest {
            largest = number;
        }
    }

    println!("The largest number is {largest}");
}

Code to find the largest number in two lists of numbers

Although this code works, duplicating code is tedious and error prone. We also have to remember to update the code in multiple places when we want to change it.

To eliminate this duplication, well create an abstraction by defining a function that operates on any list of integers passed in a parameter. This solution makes our code clearer and lets us express the concept of finding the largest number in a list abstractly.

In Listing 10-3, we extract the code that finds the largest number into a function named largest. Then we call the function to find the largest number in the two lists from Listing 10-2. We could also use the function on any other list of i32 values we might have in the future.

Filename: src/main.rs

fn largest(list: &[i32]) -> &i32 {
    let mut largest = &list[0];

    for item in list {
        if item > largest {
            largest = item;
        }
    }

    largest
}

fn main() {
    let number_list = vec![34, 50, 25, 100, 65];

    let result = largest(&number_list);
    println!("The largest number is {result}");

    let number_list = vec![102, 34, 6000, 89, 54, 2, 43, 8];

    let result = largest(&number_list);
    println!("The largest number is {result}");
}

Abstracted code to find the largest number in two lists

The largest function has a parameter called list, which represents any concrete slice of i32 values we might pass into the function. As a result, when we call the function, the code runs on the specific values that we pass in.

In summary, here are the steps we took to change the code from Listing 10-2 to Listing 10-3:

  1. Identify duplicate code.
  2. Extract the duplicate code into the body of the function, and specify the inputs and return values of that code in the function signature.
  3. Update the two instances of duplicated code to call the function instead. Next, well use these same steps with generics to reduce code duplication. In the same way that the function body can operate on an abstract list instead of specific values, generics allow code to operate on abstract types.

For example, say we had two functions: one that finds the largest item in a slice of i32 values and one that finds the largest item in a slice of char values. How would we eliminate that duplication? Lets find out!

Generic Data Types

We use generics to create definitions for items like function signatures or structs, which we can then use with many different concrete data types. Lets first look at how to define functions, structs, enums, and methods using generics. Then well discuss how generics affect code performance.

In Function Definitions

When defining a function that uses generics, we place the generics in the signature of the function where we would usually specify the data types of the parameters and return value. Doing so makes our code more flexible and provides more functionality to callers of our function while preventing code duplication.

Continuing with our largest function, Listing 10-4 shows two functions that both find the largest value in a slice. Well then combine these into a single function that uses generics.

Filename: src/main.rs

fn largest_i32(list: &[i32]) -> &i32 {
    let mut largest = &list[0];

    for item in list {
        if item > largest {
            largest = item;
        }
    }

    largest
}

fn largest_char(list: &[char]) -> &char {
    let mut largest = &list[0];

    for item in list {
        if item > largest {
            largest = item;
        }
    }

    largest
}

fn main() {
    let number_list = vec![34, 50, 25, 100, 65];

    let result = largest_i32(&number_list);
    println!("The largest number is {result}");

    let char_list = vec!['y', 'm', 'a', 'q'];

    let result = largest_char(&char_list);
    println!("The largest char is {result}");
}

Two functions that differ only in their names and in the types in their signatures

The largest_i32 function is the one we extracted in Listing 10-3 that finds the largest i32 in a slice. The largest_char function finds the largest char in a slice. The function bodies have the same code, so lets eliminate the duplication by introducing a generic type parameter in a single function.

To parameterize the types in a new single function, we need to name the type parameter, just as we do for the value parameters to a function. You can use any identifier as a type parameter name. But well use T because, by convention, type parameter names in Rust are short, often just one letter, and Rusts type-naming convention is CamelCase. Short for type, T is the default choice of most Rust programmers.

When we use a parameter in the body of the function, we have to declare the parameter name in the signature so the compiler knows what that name means. Similarly, when we use a type parameter name in a function signature, we have to declare the type parameter name before we use it. To define the generic largest function, we place type name declarations inside angle brackets, <>, between the name of the function and the parameter list, like this:

fn largest<T>(list: &[T]) -> &T {

We read this definition as: the function largest is generic over some type T. This function has one parameter named list, which is a slice of values of type T. The largest function will return a reference to a value of the same type T.

Listing 10-5 shows the combined largest function definition using the generic data type in its signature. The listing also shows how we can call the function with either a slice of i32 values or char values. Note that this code wont compile yet, but well fix it later in this chapter.

Filename: src/main.rs

fn largest<T>(list: &[T]) -> &T {
    let mut largest = &list[0];

    for item in list {
        if item > largest {
            largest = item;
        }
    }

    largest
}

fn main() {
    let number_list = vec![34, 50, 25, 100, 65];

    let result = largest(&number_list);
    println!("The largest number is {result}");

    let char_list = vec!['y', 'm', 'a', 'q'];

    let result = largest(&char_list);
    println!("The largest char is {result}");
}

The largest function using generic type parameters; this doesnt compile yet

If we compile this code right now, well get this error:

error[E0369]: binary operation `>` cannot be applied to type `&T`
 --> src/main.rs:5:17
  |
5 |         if item > largest {
  |            ---- ^ ------- &T
  |            |
  |            &T
  |
help: consider restricting type parameter `T`
  |
1 | fn largest<T: std::cmp::PartialOrd>(list: &[T]) -> &T {
  |             ++++++++++++++++++++++

The help text mentions std::cmp::PartialOrd, which is a trait, and were going to talk about traits in the next section. For now, know that this error states that the body of largest wont work for all possible types that T could be. Because we want to compare values of type T in the body, we can only use types whose values can be ordered. To enable comparisons, the standard library has the std::cmp::PartialOrd trait that you can implement on types (see Appendix C for more on this trait). By following the help texts suggestion, we restrict the types valid for T to only those that implement PartialOrd and this example will compile, because the standard library implements PartialOrd on both i32 and char.

In Struct Definitions

We can also define structs to use a generic type parameter in one or more fields using the <> syntax. Listing 10-6 defines a Point<T> struct to hold x and y coordinate values of any type.

Filename: src/main.rs

1 struct Point<T> {
  2 x: T,
  3 y: T,
}

fn main() {
    let integer = Point { x: 5, y: 10 };
    let float = Point { x: 1.0, y: 4.0 };
}

A Point<T> struct that holds x and y values of type T

The syntax for using generics in struct definitions is similar to that used in function definitions. First we declare the name of the type parameter inside angle brackets just after the name of the struct [1]. Then we use the generic type in the struct definition where we would otherwise specify concrete data types [23].

Note that because weve used only one generic type to define Point<T>, this definition says that the Point<T> struct is generic over some type T, and the fields x and y are both that same type, whatever that type may be. If we create an instance of a Point<T> that has values of different types, as in Listing 10-7, our code wont compile.

Filename: src/main.rs

struct Point<T> {
    x: T,
    y: T,
}

fn main() {
    let wont_work = Point { x: 5, y: 4.0 };
}

The fields x and y must be the same type because both have the same generic data type T.

In this example, when we assign the integer value 5 to x, we let the compiler know that the generic type T will be an integer for this instance of Point<T>. Then when we specify 4.0 for y, which weve defined to have the same type as x, well get a type mismatch error like this:

error[E0308]: mismatched types
 --> src/main.rs:7:38
  |
7 |     let wont_work = Point { x: 5, y: 4.0 };
  |                                      ^^^ expected integer, found floating-
point number

To define a Point struct where x and y are both generics but could have different types, we can use multiple generic type parameters. For example, in Listing 10-8, we change the definition of Point to be generic over types T and U where x is of type T and y is of type U.

Filename: src/main.rs

struct Point<T, U> {
    x: T,
    y: U,
}

fn main() {
    let both_integer = Point { x: 5, y: 10 };
    let both_float = Point { x: 1.0, y: 4.0 };
    let integer_and_float = Point { x: 5, y: 4.0 };
}

A Point<T, U> generic over two types so that x and y can be values of different types

Now all the instances of Point shown are allowed! You can use as many generic type parameters in a definition as you want, but using more than a few makes your code hard to read. If youre finding you need lots of generic types in your code, it could indicate that your code needs restructuring into smaller pieces.

In Enum Definitions

As we did with structs, we can define enums to hold generic data types in their variants. Lets take another look at the Option<T> enum that the standard library provides, which we used in Chapter 6:

enum Option<T> {
    Some(T),
    None,
}

This definition should now make more sense to you. As you can see, the Option<T> enum is generic over type T and has two variants: Some, which holds one value of type T, and a None variant that doesnt hold any value. By using the Option<T> enum, we can express the abstract concept of an optional value, and because Option<T> is generic, we can use this abstraction no matter what the type of the optional value is.

Enums can use multiple generic types as well. The definition of the Result enum that we used in Chapter 9 is one example:

enum Result<T, E> {
    Ok(T),
    Err(E),
}

The Result enum is generic over two types, T and E, and has two variants: Ok, which holds a value of type T, and Err, which holds a value of type E. This definition makes it convenient to use the Result enum anywhere we have an operation that might succeed (return a value of some type T) or fail (return an error of some type E). In fact, this is what we used to open a file in Listing 9-3, where T was filled in with the type std::fs::File when the file was opened successfully and E was filled in with the type std::io::Error when there were problems opening the file.

When you recognize situations in your code with multiple struct or enum definitions that differ only in the types of the values they hold, you can avoid duplication by using generic types instead.

In Method Definitions

We can implement methods on structs and enums (as we did in Chapter 5) and use generic types in their definitions too. Listing 10-9 shows the Point<T> struct we defined in Listing 10-6 with a method named x implemented on it.

Filename: src/main.rs

struct Point<T> {
    x: T,
    y: T,
}

impl<T> Point<T> {
    fn x(&self) -> &T {
        &self.x
    }
}

fn main() {
    let p = Point { x: 5, y: 10 };

    println!("p.x = {}", p.x());
}

Implementing a method named x on the Point<T> struct that will return a reference to the x field of type T

Here, weve defined a method named x on Point<T> that returns a reference to the data in the field x.

Note that we have to declare T just after impl so we can use T to specify that were implementing methods on the type Point<T>. By declaring T as a generic type after impl, Rust can identify that the type in the angle brackets in Point is a generic type rather than a concrete type. We could have chosen a different name for this generic parameter than the generic parameter declared in the struct definition, but using the same name is conventional. Methods written within an impl that declares the generic type will be defined on any instance of the type, no matter what concrete type ends up substituting for the generic type.

We can also specify constraints on generic types when defining methods on the type. We could, for example, implement methods only on Point<f32> instances rather than on Point<T> instances with any generic type. In Listing 10-10 we use the concrete type f32, meaning we dont declare any types after impl.

Filename: src/main.rs

impl Point<f32> {
    fn distance_from_origin(&self) -> f32 {
        (self.x.powi(2) + self.y.powi(2)).sqrt()
    }
}

An impl block that only applies to a struct with a particular concrete type for the generic type parameter T

This code means the type Point<f32> will have a distance_from_origin method; other instances of Point<T> where T is not of type f32 will not have this method defined. The method measures how far our point is from the point at coordinates (0.0, 0.0) and uses mathematical operations that are available only for floating-point types.

Generic type parameters in a struct definition arent always the same as those you use in that same structs method signatures. Listing 10-11 uses the generic types X1 and Y1 for the Point struct and X2 Y2 for the mixup method signature to make the example clearer. The method creates a new Point instance with the x value from the self Point (of type X1) and the y value from the passed-in Point (of type Y2).

Filename: src/main.rs

struct Point<X1, Y1> {
    x: X1,
    y: Y1,
}

1 impl<X1, Y1> Point<X1, Y1> {
  2 fn mixup<X2, Y2>(self, other: Point<X2, Y2>) -> Point<X1, Y2> {
        Point {
            x: self.x,
            y: other.y,
        }
    }
}

fn main() {
  3 let p1 = Point { x: 5, y: 10.4 };
  4 let p2 = Point { x: "Hello", y: 'c' };

  5 let p3 = p1.mixup(p2);

  6 println!("p3.x = {}, p3.y = {}", p3.x, p3.y);
}

A method that uses generic types different from its structs definition

In main, weve defined a Point that has an i32 for x (with value 5) and an f64 for y (with value 10.4 [3]). The p2 variable is a Point struct that has a string slice for x (with value "Hello") and a char for y (with value c [4]). Calling mixup on p1 with the argument p2 gives us p3 [5], which will have an i32 for x because x came from p1. The p3 variable will have a char for y because y came from p2. The println! macro call [6] will print p3.x = 5, p3.y = c.

The purpose of this example is to demonstrate a situation in which some generic parameters are declared with impl and some are declared with the method definition. Here, the generic parameters X1 and Y1 are declared after impl [1] because they go with the struct definition. The generic parameters X2 and Y2 are declared after fn mixup [2] because theyre only relevant to the method.

Performance of Code Using Generics

You might be wondering whether there is a runtime cost when using generic type parameters. The good news is that using generic types wont make your program run any slower than it would with concrete types.

Rust accomplishes this by performing monomorphization of the code using generics at compile time. Monomorphization is the process of turning generic code into specific code by filling in the concrete types that are used when compiled. In this process, the compiler does the opposite of the steps we used to create the generic function in Listing 10-5: the compiler looks at all the places where generic code is called and generates code for the concrete types the generic code is called with.

Lets look at how this works by using the standard librarys generic Option<T> enum:

let integer = Some(5);
let float = Some(5.0);

When Rust compiles this code, it performs monomorphization. During that process, the compiler reads the values that have been used in Option<T> instances and identifies two kinds of Option<T>: one is i32 and the other is f64. As such, it expands the generic definition of Option<T> into two definitions specialized to i32 and f64, thereby replacing the generic definition with the specific ones.

The monomorphized version of the code looks similar to the following (the compiler uses different names than what were using here for illustration):

Filename: src/main.rs

enum Option_i32 {
    Some(i32),
    None,
}

enum Option_f64 {
    Some(f64),
    None,
}

fn main() {
    let integer = Option_i32::Some(5);
    let float = Option_f64::Some(5.0);
}

The generic Option<T> is replaced with the specific definitions created by the compiler. Because Rust compiles generic code into code that specifies the type in each instance, we pay no runtime cost for using generics. When the code runs, it performs just as it would if we had duplicated each definition by hand. The process of monomorphization makes Rusts generics extremely efficient at runtime.

Traits: Defining Shared Behavior

A trait defines the functionality a particular type has and can share with other types. We can use traits to define shared behavior in an abstract way. We can use trait bounds to specify that a generic type can be any type that has certain behavior.

NoteTraits are similar to a feature often called interfaces in other languages, although with some differences.

Defining a Trait

A types behavior consists of the methods we can call on that type. Different types share the same behavior if we can call the same methods on all of those types. Trait definitions are a way to group method signatures together to define a set of behaviors necessary to accomplish some purpose.

For example, lets say we have multiple structs that hold various kinds and amounts of text: a NewsArticle struct that holds a news story filed in a particular location and a Tweet that can have, at most, 280 characters along with metadata that indicates whether it was a new tweet, a retweet, or a reply to another tweet.

We want to make a media aggregator library crate named aggregator that can display summaries of data that might be stored in a NewsArticle or Tweet instance. To do this, we need a summary from each type, and well request that summary by calling a summarize method on an instance. Listing 10-12 shows the definition of a public Summary trait that expresses this behavior.

Filename: src/lib.rs

pub trait Summary {
    fn summarize(&self) -> String;
}

A Summary trait that consists of the behavior provided by a summarize method

Here, we declare a trait using the trait keyword and then the traits name, which is Summary in this case. We also declare the trait as pub so that crates depending on this crate can make use of this trait too, as well see in a few examples. Inside the curly brackets, we declare the method signatures that describe the behaviors of the types that implement this trait, which in this case is fn summarize(&self) -> String.

After the method signature, instead of providing an implementation within curly brackets, we use a semicolon. Each type implementing this trait must provide its own custom behavior for the body of the method. The compiler will enforce that any type that has the Summary trait will have the method summarize defined with this signature exactly.

A trait can have multiple methods in its body: the method signatures are listed one per line, and each line ends in a semicolon.

Implementing a Trait on a Type

Now that weve defined the desired signatures of the Summary traits methods, we can implement it on the types in our media aggregator. Listing 10-13 shows an implementation of the Summary trait on the NewsArticle struct that uses the headline, the author, and the location to create the return value of summarize. For the Tweet struct, we define summarize as the username followed by the entire text of the tweet, assuming that the tweet content is already limited to 280 characters.

Filename: src/lib.rs

pub struct NewsArticle {
    pub headline: String,
    pub location: String,
    pub author: String,
    pub content: String,
}

impl Summary for NewsArticle {
    fn summarize(&self) -> String {
        format!(
            "{}, by {} ({})",
            self.headline,
            self.author,
            self.location
        )
    }
}

pub struct Tweet {
    pub username: String,
    pub content: String,
    pub reply: bool,
    pub retweet: bool,
}

impl Summary for Tweet {
    fn summarize(&self) -> String {
        format!("{}: {}", self.username, self.content)
    }
}

Implementing the Summary trait on the NewsArticle and Tweet types

Implementing a trait on a type is similar to implementing regular methods. The difference is that after impl, we put the trait name we want to implement, then use the for keyword, and then specify the name of the type we want to implement the trait for. Within the impl block, we put the method signatures that the trait definition has defined. Instead of adding a semicolon after each signature, we use curly brackets and fill in the method body with the specific behavior that we want the methods of the trait to have for the particular type.

Now that the library has implemented the Summary trait on NewsArticle and Tweet, users of the crate can call the trait methods on instances of NewsArticle and Tweet in the same way we call regular methods. The only difference is that the user must bring the trait into scope as well as the types. Heres an example of how a binary crate could use our aggregator library crate:

use aggregator::{Summary, Tweet};

fn main() {
    let tweet = Tweet {
        username: String::from("horse_ebooks"),
        content: String::from(
            "of course, as you probably already know, people",
        ),
        reply: false,
        retweet: false,
    };

    println!("1 new tweet: {}", tweet.summarize());
}

This code prints 1 new tweet: horse_ebooks: of course, as you probably already know, people.

Other crates that depend on the aggregator crate can also bring the Summary trait into scope to implement Summary on their own types. One restriction to note is that we can implement a trait on a type only if at least one of the trait or the type is local to our crate. For example, we can implement standard library traits like Display on a custom type like Tweet as part of our aggregator crate functionality because the type Tweet is local to our aggregator crate. We can also implement Summary on Vec<T> in our aggregator crate because the trait Summary is local to our aggregator crate.

But we cant implement external traits on external types. For example, we cant implement the Display trait on Vec<T> within our aggregator crate because Display and Vec<T> are both defined in the standard library and arent local to our aggregator crate. This restriction is part of a property called coherence, and more specifically the orphan rule, so named because the parent type is not present. This rule ensures that other peoples code cant break your code and vice versa. Without the rule, two crates could implement the same trait for the same type, and Rust wouldnt know which implementation to use.

Default Implementations

Sometimes its useful to have default behavior for some or all of the methods in a trait instead of requiring implementations for all methods on every type. Then, as we implement the trait on a particular type, we can keep or override each methods default behavior.

In Listing 10-14, we specify a default string for the summarize method of the Summary trait instead of only defining the method signature, as we did in Listing 10-12.

Filename: src/lib.rs

pub trait Summary {
    fn summarize(&self) -> String {
        String::from("(Read more...)")
    }
}

Defining a Summary trait with a default implementation of the summarize method

To use a default implementation to summarize instances of NewsArticle, we specify an empty impl block with impl Summary for NewsArticle {}.

Even though were no longer defining the summarize method on NewsArticle directly, weve provided a default implementation and specified that NewsArticle implements the Summary trait. As a result, we can still call the summarize method on an instance of NewsArticle, like this:

let article = NewsArticle {
    headline: String::from(
        "Penguins win the Stanley Cup Championship!"
    ),
    location: String::from("Pittsburgh, PA, USA"),
    author: String::from("Iceburgh"),
    content: String::from(
        "The Pittsburgh Penguins once again are the best \
         hockey team in the NHL.",
    ),
};

println!("New article available! {}", article.summarize());

Unmatched: BodyContinued Creating a default implementation doesnt require us to change anything about the implementation of Summary on Tweet in Listing 10-13. The reason is that the syntax for overriding a default implementation is the same as the syntax for implementing a trait method that doesnt have a default implementation.

Default implementations can call other methods in the same trait, even if those other methods dont have a default implementation. In this way, a trait can provide a lot of useful functionality and only require implementors to specify a small part of it. For example, we could define the Summary trait to have a summarize_author method whose implementation is required, and then define a summarize method that has a default implementation that calls the summarize_author method:

pub trait Summary {
    fn summarize_author(&self) -> String;

    fn summarize(&self) -> String {
        format!(
            "(Read more from {}...)",
            self.summarize_author()
        )
    }
}

To use this version of Summary, we only need to define summarize_author when we implement the trait on a type:

impl Summary for Tweet {
    fn summarize_author(&self) -> String {
        format!("@{}", self.username)
    }
}

After we define summarize_author, we can call summarize on instances of the Tweet struct, and the default implementation of summarize will call the definition of summarize_author that weve provided. Because weve implemented summarize_author, the Summary trait has given us the behavior of the summarize method without requiring us to write any more code. Heres what that looks like:

let tweet = Tweet {
    username: String::from("horse_ebooks"),
    content: String::from(
        "of course, as you probably already know, people",
    ),
    reply: false,
    retweet: false,
};

println!("1 new tweet: {}", tweet.summarize());

This code prints 1 new tweet: (Read more from @horse_ebooks...).

Note that it isnt possible to call the default implementation from an overriding implementation of that same method.

Traits as Parameters

Now that you know how to define and implement traits, we can explore how to use traits to define functions that accept many different types. Well use the Summary trait we implemented on the NewsArticle and Tweet types in Listing 10-13 to define a notify function that calls the summarize method on its item parameter, which is of some type that implements the Summary trait. To do this, we use the impl Trait syntax, like this:

pub fn notify(item: &impl Summary) {
    println!("Breaking news! {}", item.summarize());
}

Instead of a concrete type for the item parameter, we specify the impl keyword and the trait name. This parameter accepts any type that implements the specified trait. In the body of notify, we can call any methods on item that come from the Summary trait, such as summarize. We can call notify and pass in any instance of NewsArticle or Tweet. Code that calls the function with any other type, such as a String or an i32, wont compile because those types dont implement Summary.

Trait Bound Syntax

The impl Trait syntax works for straightforward cases but is actually syntax sugar for a longer form known as a trait bound; it looks like this:

pub fn notify<T: Summary>(item: &T) {
    println!("Breaking news! {}", item.summarize());
}

This longer form is equivalent to the example in the previous section but is more verbose. We place trait bounds with the declaration of the generic type parameter after a colon and inside angle brackets.

The impl Trait syntax is convenient and makes for more concise code in simple cases, while the fuller trait bound syntax can express more complexity in other cases. For example, we can have two parameters that implement Summary. Doing so with the impl Trait syntax looks like this:

pub fn notify(item1: &impl Summary, item2: &impl Summary) {

Using impl Trait is appropriate if we want this function to allow item1 and item2 to have different types (as long as both types implement Summary). If we want to force both parameters to have the same type, however, we must use a trait bound, like this:

pub fn notify<T: Summary>(item1: &T, item2: &T) {

The generic type T specified as the type of the item1 and item2 parameters constrains the function such that the concrete type of the value passed as an argument for item1 and item2 must be the same.

Specifying Multiple Trait Bounds with the + Syntax

We can also specify more than one trait bound. Say we wanted notify to use display formatting as well as summarize on item: we specify in the notify definition that item must implement both Display and Summary. We can do so using the + syntax:

pub fn notify(item: &(impl Summary + Display)) {

The + syntax is also valid with trait bounds on generic types:

pub fn notify<T: Summary + Display>(item: &T) {

With the two trait bounds specified, the body of notify can call summarize and use {} to format item.

Clearer Trait Bounds with where Clauses

Using too many trait bounds has its downsides. Each generic has its own trait bounds, so functions with multiple generic type parameters can contain lots of trait bound information between the functions name and its parameter list, making the function signature hard to read. For this reason, Rust has alternate syntax for specifying trait bounds inside a where clause after the function signature. So, instead of writing this:

fn some_function<T: Display + Clone, U: Clone + Debug>(t: &T, u: &U) -> i32 {

Unmatched: BodyContinued ``` fn some_function<T, U>(t: &T, u: &U) -> i32


where


T: Display + Clone,

U: Clone + Debug,

{


This functions signature is less cluttered: the function name, parameter list,
and return type are close together, similar to a function without lots of trait
bounds.

### Returning Types That Implement Traits

We can also use the `impl Trait` syntax in the return position to return a
value of some type that implements a trait, as shown here:

fn returns_summarizable() -> impl Summary {


Tweet {

    username: String::from("horse_ebooks"),

    content: String::from(

        "of course, as you probably already know, people",

    ),

    reply: false,

    retweet: false,

}

}


By using `impl Summary` for the return type, we specify that the
`returns_summarizable` function returns some type that implements the `Summary`
trait without naming the concrete type. In this case, `returns_summarizable`
returns a `Tweet`, but the code calling this function doesnt need to know that.

The ability to specify a return type only by the trait it implements is
especially useful in the context of closures and iterators, which we cover in
Chapter 13. Closures and iterators create types that only the compiler knows or
types that are very long to specify. The `impl Trait` syntax lets you concisely
specify that a function returns some type that implements the `Iterator` trait
without needing to write out a very long type.

However, you can only use `impl Trait` if youre returning a single type. For
example, this code that returns either a `NewsArticle` or a `Tweet` with the
return type specified as `impl Summary` wouldnt work:

fn returns_summarizable(switch: bool) -> impl Summary {


if switch {

    NewsArticle {

        headline: String::from(

            "Penguins win the Stanley Cup Championship!",

        ),

        location: String::from("Pittsburgh, PA, USA"),

        author: String::from("Iceburgh"),

        content: String::from(

            "The Pittsburgh Penguins once again are the best \

             hockey team in the NHL.",

        ),

    }

} else {

    Tweet {

        username: String::from("horse_ebooks"),

        content: String::from(

            "of course, as you probably already know, people",

        ),

        reply: false,

        retweet: false,

    }

}

}


Returning either a `NewsArticle` or a `Tweet` isnt allowed due to restrictions
around how the `impl Trait` syntax is implemented in the compiler. Well cover
how to write a function with this behavior in “Using Trait Objects That Allow
for Values of Different Types” on page XX.

### Using Trait Bounds to Conditionally Implement Methods

By using a trait bound with an `impl` block that uses generic type parameters,
we can implement methods conditionally for types that implement the specified
traits. For example, the type `Pair<T>` in Listing 10-15 always implements the
`new` function to return a new instance of `Pair<T>` (recall from “Defining
Methods” on page XX that `Self` is a type alias for the type of the `impl`
block, which in this case is `Pair<T>`). But in the next `impl` block,
`Pair<T>` only implements the `cmp_display` method if its inner type `T`
implements the `PartialOrd` trait that enables comparison *and* the `Display`
trait that enables printing.

Filename: src/lib.rs

use std::fmt::Display;



struct Pair {


x: T,

y: T,

}



impl Pair {


fn new(x: T, y: T) -> Self {

    Self { x, y }

}

}



impl<T: Display + PartialOrd> Pair {


fn cmp_display(&self) {

    if self.x >= self.y {

        println!("The largest member is x = {}", self.x);

    } else {

        println!("The largest member is y = {}", self.y);

    }

}

}


Conditionally implementing methods on a generic type depending on trait bounds

We can also conditionally implement a trait for any type that implements
another trait. Implementations of a trait on any type that satisfies the trait
bounds are called *blanket implementations* and are used extensively in the
Rust standard library. For example, the standard library implements the
`ToString` trait on any type that implements the `Display` trait. The `impl`
block in the standard library looks similar to this code:

impl<T: Display> ToString for T {


--snip--

}


Because the standard library has this blanket implementation, we can call the
`to_string` method defined by the `ToString` trait on any type that implements
the `Display` trait. For example, we can turn integers into their corresponding
`String` values like this because integers implement `Display`:

let s = 3.to_string();


Blanket implementations appear in the documentation for the trait in the
“Implementors” section.

Traits and trait bounds let us write code that uses generic type parameters to
reduce duplication but also specify to the compiler that we want the generic
type to have particular behavior. The compiler can then use the trait bound
information to check that all the concrete types used with our code provide the
correct behavior. In dynamically typed languages, we would get an error at
runtime if we called a method on a type which didnt define the method. But
Rust moves these errors to compile time so were forced to fix the problems
before our code is even able to run. Additionally, we dont have to write code
that checks for behavior at runtime because weve already checked at compile
time. Doing so improves performance without having to give up the flexibility
of generics.

## Validating References with Lifetimes

Lifetimes are another kind of generic that weve already been using. Rather
than ensuring that a type has the behavior we want, lifetimes ensure that
references are valid as long as we need them to be.

One detail we didnt discuss in “References and Borrowing” on page XX is that
every reference in Rust has a *lifetime*, which is the scope for which that
reference is valid. Most of the time, lifetimes are implicit and inferred, just
like most of the time, types are inferred. We must annotate types only when
multiple types are possible. In a similar way, we must annotate lifetimes when
the lifetimes of references could be related in a few different ways. Rust
requires us to annotate the relationships using generic lifetime parameters to
ensure the actual references used at runtime will definitely be valid.

Annotating lifetimes is not even a concept most other programming languages
have, so this is going to feel unfamiliar. Although we wont cover lifetimes in
their entirety in this chapter, well discuss common ways you might encounter
lifetime syntax so you can get comfortable with the concept.

### Preventing Dangling References with Lifetimes

The main aim of lifetimes is to prevent *dangling references*, which cause a
program to reference data other than the data its intended to reference.
Consider the program in Listing 10-16, which has an outer scope and an inner
scope.

fn main() {


1 let r;



{

  2 let x = 5;

  3 r = &x;

4 }



5 println!("r: {r}");


}


An attempt to use a reference whose value has gone out of scope

> NoteThe examples in Listing 10-16, 10-17, and 10-23 declare variables without
giving them an initial value, so the variable name exists in the outer scope.
At first glance, this might appear to be in conflict with Rusts having no null
values. However, if we try to use a variable before giving it a value, well
get a compile-time error, which shows that Rust indeed does not allow null
values.

The outer scope declares a variable named `r` with no initial value [1], and
the inner scope declares a variable named `x` with the initial value of `5`
[2]. Inside the inner scope, we attempt to set the value of `r` as a reference
to `x` [3]. Then the inner scope ends [4], and we attempt to print the value in
`r` [5]. This code wont compile because the value that `r` is referring to has
gone out of scope before we try to use it. Here is the error message:

error[E0597]: x does not live long enough


--> src/main.rs:6:13


|


6 | r = &x;


| ^^ borrowed value does not live long enough


7 | }


| - x dropped here while still borrowed


8 |


9 | println!("r: {r}");


| - borrow later used here


The error message says that the variable `x` “does not live long enough.” The
reason is that `x` will be out of scope when the inner scope ends on line 7.
But `r` is still valid for the outer scope; because its scope is larger, we say
that it “lives longer.” If Rust allowed this code to work, `r` would be
referencing memory that was deallocated when `x` went out of scope, and
anything we tried to do with `r` wouldnt work correctly. So how does Rust
determine that this code is invalid? It uses a borrow checker.

### The Borrow Checker

The Rust compiler has a *borrow checker* that compares scopes to determine
whether all borrows are valid. Listing 10-17 shows the same code as Listing
10-16 but with annotations showing the lifetimes of the variables.

fn main() {


let r;                // ---------+-- 'a

                      //          |

{                     //          |

    let x = 5;        // -+-- 'b  |

    r = &x;           //  |       |

}                     // -+       |

                      //          |

println!("r: {r}");   //          |

} // ---------+


Annotations of the lifetimes of `r` and `x`, named `'a` and `'b`, respectively

Here, weve annotated the lifetime of `r` with `'a` and the lifetime of `x`
with `'b`. As you can see, the inner `'b` block is much smaller than the outer
`'a` lifetime block. At compile time, Rust compares the size of the two
lifetimes and sees that `r` has a lifetime of `'a` but that it refers to memory
with a lifetime of `'b`. The program is rejected because `'b` is shorter than
`'a`: the subject of the reference doesnt live as long as the reference.

Listing 10-18 fixes the code so it doesnt have a dangling reference and it
compiles without any errors.

fn main() {


let x = 5;            // ----------+-- 'b

                      //           |

let r = &x;           // --+-- 'a  |

                      //   |       |

println!("r: {r}");   //   |       |

                      // --+       |

} // ----------+


A valid reference because the data has a longer lifetime than the reference

Here, `x` has the lifetime `'b`, which in this case is larger than `'a`. This
means `r` can reference `x` because Rust knows that the reference in `r` will
always be valid while `x` is valid.

Now that you know where the lifetimes of references are and how Rust analyzes
lifetimes to ensure references will always be valid, lets explore generic
lifetimes of parameters and return values in the context of functions.

### Generic Lifetimes in Functions

Well write a function that returns the longer of two string slices. This
function will take two string slices and return a single string slice. After
weve implemented the `longest` function, the code in Listing 10-19 should
print `The longest string is abcd`.

Filename: src/main.rs

fn main() {


let string1 = String::from("abcd");

let string2 = "xyz";


let result = longest(string1.as_str(), string2);

println!("The longest string is {result}");

}


A `main` function that calls the `longest` function to find the longer of two
string slices

Note that we want the function to take string slices, which are references,
rather than strings, because we dont want the `longest` function to take
ownership of its parameters. Refer to “String Slices as Parameters” on page XX
for more discussion about why the parameters we use in Listing 10-19 are the
ones we want.

If we try to implement the `longest` function as shown in Listing 10-20, it
wont compile.

Filename: src/main.rs

fn longest(x: &str, y: &str) -> &str {


if x.len() > y.len() {

    x

} else {

    y

}

}


An implementation of the `longest` function that returns the longer of two
string slices but does not yet compile

Instead, we get the following error that talks about lifetimes:

error[E0106]: missing lifetime specifier


--> src/main.rs:9:33


|


9 | fn longest(x: &str, y: &str) -> &str {


| ---- ---- ^ expected named lifetime parameter


|


= help: this function's return type contains a borrowed value,


but the signature does not say whether it is borrowed from x or y


help: consider introducing a named lifetime parameter


|


9 | fn longest<'a>(x: &'a str, y: &'a str) -> &'a str {


| ++++ ++ ++ ++


The help text reveals that the return type needs a generic lifetime parameter
on it because Rust cant tell whether the reference being returned refers to
`x` or `y`. Actually, we dont know either, because the `if` block in the body
of this function returns a reference to `x` and the `else` block returns a
reference to `y`!

When were defining this function, we dont know the concrete values that will
be passed into this function, so we dont know whether the `if` case or the
`else` case will execute. We also dont know the concrete lifetimes of the
references that will be passed in, so we cant look at the scopes as we did in
Listings 10-17 and 10-18 to determine whether the reference we return will
always be valid. The borrow checker cant determine this either, because it
doesnt know how the lifetimes of `x` and `y` relate to the lifetime of the
return value. To fix this error, well add generic lifetime parameters that
define the relationship between the references so the borrow checker can
perform its analysis.

### Lifetime Annotation Syntax

Lifetime annotations dont change how long any of the references live. Rather,
they describe the relationships of the lifetimes of multiple references to each
other without affecting the lifetimes. Just as functions can accept any type
when the signature specifies a generic type parameter, functions can accept
references with any lifetime by specifying a generic lifetime parameter.

Lifetime annotations have a slightly unusual syntax: the names of lifetime
parameters must start with an apostrophe (`'`) and are usually all lowercase
and very short, like generic types. Most people use the name `'a` for the first
lifetime annotation. We place lifetime parameter annotations after the `&` of a
reference, using a space to separate the annotation from the references type.

Here are some examples: a reference to an `i32` without a lifetime parameter, a
reference to an `i32` that has a lifetime parameter named `'a`, and a mutable
reference to an `i32` that also has the lifetime `'a`.

&i32 // a reference


&'a i32 // a reference with an explicit lifetime


&'a mut i32 // a mutable reference with an explicit lifetime


One lifetime annotation by itself doesnt have much meaning because the
annotations are meant to tell Rust how generic lifetime parameters of multiple
references relate to each other. Lets examine how the lifetime annotations
relate to each other in the context of the `longest` function.

### Lifetime Annotations in Function Signatures

To use lifetime annotations in function signatures, we need to declare the
generic *lifetime* parameters inside angle brackets between the function name
and the parameter list, just as we did with generic *type* parameters.

We want the signature to express the following constraint: the returned
reference will be valid as long as both the parameters are valid. This is the
relationship between lifetimes of the parameters and the return value. Well
name the lifetime `'a` and then add it to each reference, as shown in Listing
10-21.

Filename: src/main.rs

fn longest<'a>(x: &'a str, y: &'a str) -> &'a str {


if x.len() > y.len() {

    x

} else {

    y

}

}


The `longest` function definition specifying that all the references in the
signature must have the same lifetime `'a`

This code should compile and produce the result we want when we use it with the
`main` function in Listing 10-19.

The function signature now tells Rust that for some lifetime `'a`, the function
takes two parameters, both of which are string slices that live at least as
long as lifetime `'a`. The function signature also tells Rust that the string
slice returned from the function will live at least as long as lifetime `'a`.
In practice, it means that the lifetime of the reference returned by the
`longest` function is the same as the smaller of the lifetimes of the values
referred to by the function arguments. These relationships are what we want
Rust to use when analyzing this code.

Remember, when we specify the lifetime parameters in this function signature,
were not changing the lifetimes of any values passed in or returned. Rather,
were specifying that the borrow checker should reject any values that dont
adhere to these constraints. Note that the `longest` function doesnt need to
know exactly how long `x` and `y` will live, only that some scope can be
substituted for `'a` that will satisfy this signature.

When annotating lifetimes in functions, the annotations go in the function
signature, not in the function body. The lifetime annotations become part of
the contract of the function, much like the types in the signature. Having
function signatures contain the lifetime contract means the analysis the Rust
compiler does can be simpler. If theres a problem with the way a function is
annotated or the way it is called, the compiler errors can point to the part of
our code and the constraints more precisely. If, instead, the Rust compiler
made more inferences about what we intended the relationships of the lifetimes
to be, the compiler might only be able to point to a use of our code many steps
away from the cause of the problem.

When we pass concrete references to `longest`, the concrete lifetime that is
substituted for `'a` is the part of the scope of `x` that overlaps with the
scope of `y`. In other words, the generic lifetime `'a` will get the concrete
lifetime that is equal to the smaller of the lifetimes of `x` and `y`. Because
weve annotated the returned reference with the same lifetime parameter `'a`,
the returned reference will also be valid for the length of the smaller of the
lifetimes of `x` and `y`.

Lets look at how the lifetime annotations restrict the `longest` function by
passing in references that have different concrete lifetimes. Listing 10-22 is
a straightforward example.

Filename: src/main.rs

fn main() {


let string1 = String::from("long string is long");


{

    let string2 = String::from("xyz");

    let result = longest(string1.as_str(), string2.as_str());

    println!("The longest string is {result}");

}

}


Using the `longest` function with references to `String` values that have
different concrete lifetimes

In this example, `string1` is valid until the end of the outer scope, `string2`
is valid until the end of the inner scope, and `result` references something
that is valid until the end of the inner scope. Run this code and youll see
that the borrow checker approves; it will compile and print `The longest string
is long string is long`.

Next, lets try an example that shows that the lifetime of the reference in
`result` must be the smaller lifetime of the two arguments. Well move the
declaration of the `result` variable outside the inner scope but leave the
assignment of the value to the `result` variable inside the scope with
`string2`. Then well move the `println!` that uses `result` to outside the
inner scope, after the inner scope has ended. The code in Listing 10-23 will
not compile.

Filename: src/main.rs

fn main() {


let string1 = String::from("long string is long");

let result;

{

    let string2 = String::from("xyz");

    result = longest(string1.as_str(), string2.as_str());

}

println!("The longest string is {result}");

}


Attempting to use `result` after `string2` has gone out of scope

When we try to compile this code, we get this error:

error[E0597]: string2 does not live long enough


--> src/main.rs:6:44


|


6 | result = longest(string1.as_str(), string2.as_str());


| ^^^^^^^^^^^^^^^^ borrowed value


does not live long enough


7 | }


| - string2 dropped here while still borrowed


8 | println!("The longest string is {result}");


| ------ borrow later used here


The error shows that for `result` to be valid for the `println!` statement,
`string2` would need to be valid until the end of the outer scope. Rust knows
this because we annotated the lifetimes of the function parameters and return
values using the same lifetime parameter `'a`.

As humans, we can look at this code and see that `string1` is longer than
`string2`, and therefore, `result` will contain a reference to `string1`.
Because `string1` has not gone out of scope yet, a reference to `string1` will
still be valid for the `println!` statement. However, the compiler cant see
that the reference is valid in this case. Weve told Rust that the lifetime of
the reference returned by the `longest` function is the same as the smaller of
the lifetimes of the references passed in. Therefore, the borrow checker
disallows the code in Listing 10-23 as possibly having an invalid reference.

Try designing more experiments that vary the values and lifetimes of the
references passed in to the `longest` function and how the returned reference
is used. Make hypotheses about whether or not your experiments will pass the
borrow checker before you compile; then check to see if youre right!

### Thinking in Terms of Lifetimes

The way in which you need to specify lifetime parameters depends on what your
function is doing. For example, if we changed the implementation of the
`longest` function to always return the first parameter rather than the longest
string slice, we wouldnt need to specify a lifetime on the `y` parameter. The
following code will compile:

Filename: src/main.rs

fn longest<'a>(x: &'a str, y: &str) -> &'a str {


x

}


Weve specified a lifetime parameter `'a` for the parameter `x` and the return
type, but not for the parameter `y`, because the lifetime of `y` does not have
any relationship with the lifetime of `x` or the return value.

When returning a reference from a function, the lifetime parameter for the
return type needs to match the lifetime parameter for one of the parameters. If
the reference returned does *not* refer to one of the parameters, it must refer
to a value created within this function. However, this would be a dangling
reference because the value will go out of scope at the end of the function.
Consider this attempted implementation of the `longest` function that wont
compile:

Filename: src/main.rs

fn longest<'a>(x: &str, y: &str) -> &'a str {


let result = String::from("really long string");

result.as_str()

}


Here, even though weve specified a lifetime parameter `'a` for the return
type, this implementation will fail to compile because the return value
lifetime is not related to the lifetime of the parameters at all. Here is the
error message we get:

error[E0515]: cannot return reference to local variable result


--> src/main.rs:11:5


|


11 | result.as_str()


| ^^^^^^^^^^^^^^^ returns a reference to data owned by the


current function


The problem is that `result` goes out of scope and gets cleaned up at the end
of the `longest` function. Were also trying to return a reference to `result`
from the function. There is no way we can specify lifetime parameters that
would change the dangling reference, and Rust wont let us create a dangling
reference. In this case, the best fix would be to return an owned data type
rather than a reference so the calling function is then responsible for
cleaning up the value.

Ultimately, lifetime syntax is about connecting the lifetimes of various
parameters and return values of functions. Once theyre connected, Rust has
enough information to allow memory-safe operations and disallow operations that
would create dangling pointers or otherwise violate memory safety.

### Lifetime Annotations in Struct Definitions

So far, the structs weve defined all hold owned types. We can define structs
to hold references, but in that case we would need to add a lifetime annotation
on every reference in the structs definition. Listing 10-24 has a struct named
`ImportantExcerpt` that holds a string slice.

Filename: src/main.rs

1 struct ImportantExcerpt<'a> {


2 part: &'a str,


}



fn main() {


3 let novel = String::from(


    "Call me Ishmael. Some years ago..."

);

4 let first_sentence = novel


    .split('.')

    .next()

    .expect("Could not find a '.'");

5 let i = ImportantExcerpt {


    part: first_sentence,

};

}


A struct that holds a reference, requiring a lifetime annotation

This struct has the single field `part` that holds a string slice, which is a
reference [2]. As with generic data types, we declare the name of the generic
lifetime parameter inside angle brackets after the name of the struct so we can
use the lifetime parameter in the body of the struct definition [1]. This
annotation means an instance of `ImportantExcerpt` cant outlive the reference
it holds in its `part` field.

The `main` function here creates an instance of the `ImportantExcerpt` struct
[5] that holds a reference to the first sentence of the `String` [4] owned by
the variable `novel` [3]. The data in `novel` exists before the
`ImportantExcerpt` instance is created. In addition, `novel` doesnt go out of
scope until after the `ImportantExcerpt` goes out of scope, so the reference in
the `ImportantExcerpt` instance is valid.

### Lifetime Elision

Youve learned that every reference has a lifetime and that you need to specify
lifetime parameters for functions or structs that use references. However, we
had a function in Listing 4-9, shown again in Listing 10-25, that compiled
without lifetime annotations.

Filename: src/lib.rs

fn first_word(s: &str) -> &str {


let bytes = s.as_bytes();


for (i, &item) in bytes.iter().enumerate() {

    if item == b' ' {

        return &s[0..i];

    }

}


&s[..]

}


A function we defined in Listing 4-9 that compiled without lifetime
annotations, even though the parameter and return type are references

The reason this function compiles without lifetime annotations is historical:
in early versions (pre-1.0) of Rust, this code wouldnt have compiled because
every reference needed an explicit lifetime. At that time, the function
signature would have been written like this:

fn first_word<'a>(s: &'a str) -> &'a str {


After writing a lot of Rust code, the Rust team found that Rust programmers
were entering the same lifetime annotations over and over in particular
situations. These situations were predictable and followed a few deterministic
patterns. The developers programmed these patterns into the compilers code so
the borrow checker could infer the lifetimes in these situations and wouldnt
need explicit annotations.

This piece of Rust history is relevant because its possible that more
deterministic patterns will emerge and be added to the compiler. In the future,
even fewer lifetime annotations might be required.

The patterns programmed into Rusts analysis of references are called the
*lifetime elision rules*. These arent rules for programmers to follow; theyre
a set of particular cases that the compiler will consider, and if your code
fits these cases, you dont need to write the lifetimes explicitly.

The elision rules dont provide full inference. If Rust deterministically
applies the rules but there is still ambiguity as to what lifetimes the
references have, the compiler wont guess what the lifetime of the remaining
references should be. Instead of guessing, the compiler will give you an error
that you can resolve by adding the lifetime annotations.

Lifetimes on function or method parameters are called *input lifetimes*   , and
lifetimes on return values are called *output lifetimes* .

The compiler uses three rules to figure out the lifetimes of the references
when there arent explicit annotations. The first rule applies to input
lifetimes, and the second and third rules apply to output lifetimes. If the
compiler gets to the end of the three rules and there are still references for
which it cant figure out lifetimes, the compiler will stop with an error.
These rules apply to `fn` definitions as well as `impl` blocks.

The first rule is that the compiler assigns a lifetime parameter to each
parameter thats a reference. In other words, a function with one parameter
gets one lifetime parameter: `fn foo<'a>(x: &'a i32)`; a function with two
parameters gets two separate lifetime parameters: `fn foo<'a, 'b>(x: &'a i32,
y: &'b i32)`; and so on.

The second rule is that, if there is exactly one input lifetime parameter, that
lifetime is assigned to all output lifetime parameters: `fn foo<'a>(x: &'a i32)
-> &'a i32`.

The third rule is that, if there are multiple input lifetime parameters, but
one of them is `&self` or `&mut self` because this is a method, the lifetime of
`self` is assigned to all output lifetime parameters. This third rule makes
methods much nicer to read and write because fewer symbols are necessary.

Lets pretend were the compiler. Well apply these rules to figure out the
lifetimes of the references in the signature of the `first_word` function in
Listing 10-25. The signature starts without any lifetimes associated with the
references:

fn first_word(s: &str) -> &str {


Then the compiler applies the first rule, which specifies that each parameter
gets its own lifetime. Well call it `'a` as usual, so now the signature is
this:

fn first_word<'a>(s: &'a str) -> &str {


The second rule applies because there is exactly one input lifetime. The second
rule specifies that the lifetime of the one input parameter gets assigned to
the output lifetime, so the signature is now this:

fn first_word<'a>(s: &'a str) -> &'a str {


Now all the references in this function signature have lifetimes, and the
compiler can continue its analysis without needing the programmer to annotate
the lifetimes in this function signature.

Lets look at another example, this time using the `longest` function that had
no lifetime parameters when we started working with it in Listing 10-20:

fn longest(x: &str, y: &str) -> &str {


Lets apply the first rule: each parameter gets its own lifetime. This time we
have two parameters instead of one, so we have two lifetimes:

fn longest<'a, 'b>(x: &'a str, y: &'b str) -> &str {


You can see that the second rule doesnt apply because there is more than one
input lifetime. The third rule doesnt apply either, because `longest` is a
function rather than a method, so none of the parameters are `self`. After
working through all three rules, we still havent figured out what the return
types lifetime is. This is why we got an error trying to compile the code in
Listing 10-20: the compiler worked through the lifetime elision rules but still
couldnt figure out all the lifetimes of the references in the signature.

Because the third rule really only applies in method signatures, well look at
lifetimes in that context next to see why the third rule means we dont have to
annotate lifetimes in method signatures very often.

### Lifetime Annotations in Method Definitions

When we implement methods on a struct with lifetimes, we use the same syntax as
that of generic type parameters shown in Listing 10-11. Where we declare and
use the lifetime parameters depends on whether theyre related to the struct
fields or the method parameters and return values.

Lifetime names for struct fields always need to be declared after the `impl`
keyword and then used after the structs name because those lifetimes are part
of the structs type.

In method signatures inside the `impl` block, references might be tied to the
lifetime of references in the structs fields, or they might be independent. In
addition, the lifetime elision rules often make it so that lifetime annotations
arent necessary in method signatures. Lets look at some examples using the
struct named `ImportantExcerpt` that we defined in Listing 10-24.

First well use a method named `level` whose only parameter is a reference to
`self` and whose return value is an `i32`, which is not a reference to anything:

impl<'a> ImportantExcerpt<'a> {


fn level(&self) -> i32 {

    3

}

}


The lifetime parameter declaration after `impl` and its use after the type name
are required, but were not required to annotate the lifetime of the reference
to `self` because of the first elision rule.

Here is an example where the third lifetime elision rule applies:

impl<'a> ImportantExcerpt<'a> {


fn announce_and_return_part(&self, announcement: &str) -> &str {

    println!("Attention please: {announcement}");

    self.part

}

}


There are two input lifetimes, so Rust applies the first lifetime elision rule
and gives both `&self` and `announcement` their own lifetimes. Then, because
one of the parameters is `&self`, the return type gets the lifetime of `&self`,
and all lifetimes have been accounted for.

### The Static Lifetime

One special lifetime we need to discuss is `'static`, which denotes that the
affected reference *can* live for the entire duration of the program. All
string literals have the `'static` lifetime, which we can annotate as follows:

let s: &'static str = "I have a static lifetime.";


The text of this string is stored directly in the programs binary, which is
always available. Therefore, the lifetime of all string literals is `'static`.

You might see suggestions to use the `'static` lifetime in error messages. But
before specifying `'static` as the lifetime for a reference, think about
whether the reference you have actually lives the entire lifetime of your
program or not, and whether you want it to. Most of the time, an error message
suggesting the `'static` lifetime results from attempting to create a dangling
reference or a mismatch of the available lifetimes. In such cases, the solution
is to fix those problems, not to specify the `'static` lifetime.

## Generic Type Parameters, Trait Bounds, and Lifetimes Together

Lets briefly look at the syntax of specifying generic type parameters, trait
bounds, and lifetimes all in one function!

use std::fmt::Display;



fn longest_with_an_announcement<'a, T>(


x: &'a str,

y: &'a str,

ann: T,

) -> &'a str


where


T: Display,

{


println!("Announcement! {ann}");

if x.len() > y.len() {

    x

} else {

    y

}

}


This is the `longest` function from Listing 10-21 that returns the longer of
two string slices. But now it has an extra parameter named `ann` of the generic
type `T`, which can be filled in by any type that implements the `Display`
trait as specified by the `where` clause. This extra parameter will be printed
using `{}`, which is why the `Display` trait bound is necessary. Because
lifetimes are a type of generic, the declarations of the lifetime parameter
`'a` and the generic type parameter `T` go in the same list inside the angle
brackets after the function name.

## Summary

We covered a lot in this chapter! Now that you know about generic type
parameters, traits and trait bounds, and generic lifetime parameters, youre
ready to write code without repetition that works in many different situations.
Generic type parameters let you apply the code to different types. Traits and
trait bounds ensure that even though the types are generic, theyll have the
behavior the code needs. You learned how to use lifetime annotations to ensure
that this flexible code wont have any dangling references. And all of this
analysis happens at compile time, which doesnt affect runtime performance!

Believe it or not, there is much more to learn on the topics we discussed in
this chapter: Chapter 17 discusses trait objects, which are another way to use
traits. There are also more complex scenarios involving lifetime annotations
that you will only need in very advanced scenarios; for those, you should read
the Rust Reference at *https://doc.rust-lang.org/reference/trait-bounds.html*.
But next, youll learn how to write tests in Rust so you can make sure your
code is working the way it should.